One integer, stored in copper. The ratios are rules and live in code; prices are content and land in M8. format() suppresses empty denominations so being broke reads as '47c', not '0g 0s 47c'. Co-Authored-By: Claude Opus 4.8 (1M context) <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_01QYa9u7Kdxv5gX4AnwWexy8
45 lines
1.4 KiB
GDScript
45 lines
1.4 KiB
GDScript
class_name Currency
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extends RefCounted
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## Money. Everything is stored in COPPER — one integer, on GameState.purse_copper.
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## The denominations exist so a bounded §6 move can name a unit (give_item(gold)
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## is +10,000c); they are NOT stored buckets, so change-making never arises.
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##
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## The ratios are rules and live here in code. PRICES are content and live in
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## /content (roadmap: "the economy is two systems"). Formatting happens only at
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## the display edge — this is the one place that knows what "12g 40s 8c" means.
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const COPPER := 1
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const SILVER := 100
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const GOLD := 10000
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const VALUES := {"copper": COPPER, "silver": SILVER, "gold": GOLD}
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static func is_currency(item_id: String) -> bool:
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return VALUES.has(item_id)
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static func value(item_id: String) -> int:
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return int(VALUES.get(item_id, 0))
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static func format(copper: int) -> String:
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# Empty denominations are suppressed and at least one unit always shows:
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# "0c", "47c", "1g 8c", "12g 40s". "0g 0s 8c" reads as a spreadsheet, not a
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# purse — and being broke should read as poverty (§3).
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if copper <= 0:
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return "0c"
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var parts: Array[String] = []
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var left := copper
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var gold := left / GOLD # int division
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if gold > 0:
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parts.append("%dg" % gold)
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left -= gold * GOLD
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var silver := left / SILVER
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if silver > 0:
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parts.append("%ds" % silver)
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left -= silver * SILVER
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if left > 0:
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parts.append("%dc" % left)
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return " ".join(parts)
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